Base | Representation |
---|---|
bin | 10000100100011101000… |
… | …100011011011111011011 |
3 | 11000212001202110010211022 |
4 | 100210131010123133123 |
5 | 122123430413041013 |
6 | 2231031311353055 |
7 | 145156623410612 |
oct | 20443504333733 |
9 | 4025052403738 |
10 | 1138654033883 |
11 | 3a999a576843 |
12 | 164818b2278b |
13 | 834b404a582 |
14 | 3d17adca879 |
15 | 1e944218008 |
hex | 1091d11b7db |
1138654033883 has 2 divisors, whose sum is σ = 1138654033884. Its totient is φ = 1138654033882.
The previous prime is 1138654033843. The next prime is 1138654033903. The reversal of 1138654033883 is 3883304568311.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1138654033883 is a prime.
It is a super-2 number, since 2×11386540338832 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1138654033843) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 569327016941 + 569327016942.
It is an arithmetic number, because the mean of its divisors is an integer number (569327016942).
Almost surely, 21138654033883 is an apocalyptic number.
1138654033883 is a deficient number, since it is larger than the sum of its proper divisors (1).
1138654033883 is an equidigital number, since it uses as much as digits as its factorization.
1138654033883 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4976640, while the sum is 53.
The spelling of 1138654033883 in words is "one trillion, one hundred thirty-eight billion, six hundred fifty-four million, thirty-three thousand, eight hundred eighty-three".
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