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11395019983 is a prime number
BaseRepresentation
bin10101001110011001…
…00011010011001111
31002102010201222210011
422213030203103033
5141314111114413
65122414454051
7552244033414
oct124714432317
932363658704
1011395019983
114918212196
122260204327
1310c7a14299
147a153a10b
1546a5bc33d
hex2a73234cf

11395019983 has 2 divisors, whose sum is σ = 11395019984. Its totient is φ = 11395019982.

The previous prime is 11395019971. The next prime is 11395019989. The reversal of 11395019983 is 38991059311.

It is a strong prime.

It is an emirp because it is prime and its reverse (38991059311) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11395019983 - 213 = 11395011791 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11395019989) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5697509991 + 5697509992.

It is an arithmetic number, because the mean of its divisors is an integer number (5697509992).

Almost surely, 211395019983 is an apocalyptic number.

11395019983 is a deficient number, since it is larger than the sum of its proper divisors (1).

11395019983 is an equidigital number, since it uses as much as digits as its factorization.

11395019983 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 262440, while the sum is 49.

The spelling of 11395019983 in words is "eleven billion, three hundred ninety-five million, nineteen thousand, nine hundred eighty-three".