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114000244133 is a prime number
BaseRepresentation
bin110101000101011110…
…0011010110110100101
3101220020212120102201012
41222022330122312211
53331433030303013
6124212044512005
711144014041536
oct1521274326645
9356225512635
10114000244133
11443901907a6
121a11654b605
13a99a1a5779
14573659c68d
152e733ba1a8
hex1a8af1ada5

114000244133 has 2 divisors, whose sum is σ = 114000244134. Its totient is φ = 114000244132.

The previous prime is 114000244109. The next prime is 114000244301. The reversal of 114000244133 is 331442000411.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 105610050529 + 8390193604 = 324977^2 + 91598^2 .

It is a cyclic number.

It is not a de Polignac number, because 114000244133 - 26 = 114000244069 is a prime.

It is a super-3 number, since 3×1140002441333 (a number of 34 digits) contains 333 as substring.

It is a Sophie Germain prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 114000244099 and 114000244108.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (114000244103) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57000122066 + 57000122067.

It is an arithmetic number, because the mean of its divisors is an integer number (57000122067).

Almost surely, 2114000244133 is an apocalyptic number.

It is an amenable number.

114000244133 is a deficient number, since it is larger than the sum of its proper divisors (1).

114000244133 is an equidigital number, since it uses as much as digits as its factorization.

114000244133 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 114000244133 its reverse (331442000411), we get a palindrome (445442244544).

The spelling of 114000244133 in words is "one hundred fourteen billion, two hundred forty-four thousand, one hundred thirty-three".