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1140010341341 is a prime number
BaseRepresentation
bin10000100101101101111…
…010010101001111011101
311000222120021120200212212
4100211231322111033131
5122134220121410331
62231414042010205
7145235343006014
oct20455572251735
94028507520785
101140010341341
113aa5261326a3
12164b371a6965
138366c03b871
143d2691a7a7b
151e9c332bd2b
hex1096de953dd

1140010341341 has 2 divisors, whose sum is σ = 1140010341342. Its totient is φ = 1140010341340.

The previous prime is 1140010341311. The next prime is 1140010341361. The reversal of 1140010341341 is 1431430100411.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 813450667225 + 326559674116 = 901915^2 + 571454^2 .

It is an emirp because it is prime and its reverse (1431430100411) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1140010341341 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1140010341311) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 570005170670 + 570005170671.

It is an arithmetic number, because the mean of its divisors is an integer number (570005170671).

Almost surely, 21140010341341 is an apocalyptic number.

It is an amenable number.

1140010341341 is a deficient number, since it is larger than the sum of its proper divisors (1).

1140010341341 is an equidigital number, since it uses as much as digits as its factorization.

1140010341341 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 576, while the sum is 23.

Adding to 1140010341341 its reverse (1431430100411), we get a palindrome (2571440441752).

The spelling of 1140010341341 in words is "one trillion, one hundred forty billion, ten million, three hundred forty-one thousand, three hundred forty-one".