Base | Representation |
---|---|
bin | 1010010111100100110101… |
… | …1010111001011111011011 |
3 | 1111100211202111121111110121 |
4 | 2211321031122321133123 |
5 | 2443234442334203233 |
6 | 40125053013254111 |
7 | 2254430102003335 |
oct | 245711532713733 |
9 | 44324674544417 |
10 | 11400142100443 |
11 | 36a5856018498 |
12 | 1341510634337 |
13 | 64904b3267a5 |
14 | 2b5aac568455 |
15 | 14b8257c192d |
hex | a5e4d6b97db |
11400142100443 has 2 divisors, whose sum is σ = 11400142100444. Its totient is φ = 11400142100442.
The previous prime is 11400142100423. The next prime is 11400142100447. The reversal of 11400142100443 is 34400124100411.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11400142100443 is a prime.
It is not a weakly prime, because it can be changed into another prime (11400142100447) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5700071050221 + 5700071050222.
It is an arithmetic number, because the mean of its divisors is an integer number (5700071050222).
Almost surely, 211400142100443 is an apocalyptic number.
11400142100443 is a deficient number, since it is larger than the sum of its proper divisors (1).
11400142100443 is an equidigital number, since it uses as much as digits as its factorization.
11400142100443 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1536, while the sum is 25.
Adding to 11400142100443 its reverse (34400124100411), we get a palindrome (45800266200854).
The spelling of 11400142100443 in words is "eleven trillion, four hundred billion, one hundred forty-two million, one hundred thousand, four hundred forty-three".
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