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1140021324241 is a prime number
BaseRepresentation
bin10000100101101110100…
…100001110100111010001
311000222121001020200120221
4100211232210032213101
5122134230424333431
62231415113233041
7145235535241102
oct20455644164721
94028531220527
101140021324241
113aa531354278
12164b3aa02781
13836713b5917
143d26a8263a9
151e9c429b111
hex1096e90e9d1

1140021324241 has 2 divisors, whose sum is σ = 1140021324242. Its totient is φ = 1140021324240.

The previous prime is 1140021324161. The next prime is 1140021324257. The reversal of 1140021324241 is 1424231200411.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 955740864400 + 184280459841 = 977620^2 + 429279^2 .

It is an emirp because it is prime and its reverse (1424231200411) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1140021324241 is a prime.

It is not a weakly prime, because it can be changed into another prime (1140021324041) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 570010662120 + 570010662121.

It is an arithmetic number, because the mean of its divisors is an integer number (570010662121).

Almost surely, 21140021324241 is an apocalyptic number.

It is an amenable number.

1140021324241 is a deficient number, since it is larger than the sum of its proper divisors (1).

1140021324241 is an equidigital number, since it uses as much as digits as its factorization.

1140021324241 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1536, while the sum is 25.

Adding to 1140021324241 its reverse (1424231200411), we get a palindrome (2564252524652).

The spelling of 1140021324241 in words is "one trillion, one hundred forty billion, twenty-one million, three hundred twenty-four thousand, two hundred forty-one".