114002500231 has 2 divisors, whose sum is σ = 114002500232. Its totient is φ = 114002500230.

The previous prime is 114002500223. The next prime is 114002500237. The reversal of 114002500231 is 132005200411.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 114002500231 - 2³ = 114002500223 is a prime.

It is a super-3 number, since 3×114002500231³ (a number of 34 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 114002500199 and 114002500208.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (114002500237) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57001250115 + 57001250116.

It is an arithmetic number, because the mean of its divisors is an integer number (57001250116).

Almost surely, 2^114002500231 is an apocalyptic number.

114002500231 is a deficient number, since it is larger than the sum of its proper divisors (1).

114002500231 is an equidigital number, since it uses as much as digits as its factorization.

114002500231 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 240, while the sum is 19.

Adding to 114002500231 its reverse (132005200411), we get a palindrome (246007700642).

The spelling of 114002500231 in words is "one hundred fourteen billion, two million, five hundred thousand, two hundred thirty-one".