Base | Representation |
---|---|
bin | 11001111010111101101010… |
… | …111011111011010110001111 |
3 | 112221122120221211012021221022 |
4 | 121322331222323323112033 |
5 | 104420311332411012312 |
6 | 1042244150050024355 |
7 | 33004311240046505 |
oct | 3172755273732617 |
9 | 487576854167838 |
10 | 114003111032207 |
11 | 333634a2139361 |
12 | 109526972780bb |
13 | 4b7c5a7788547 |
14 | 2021acc50a675 |
15 | d2a738895172 |
hex | 67af6aefb58f |
114003111032207 has 2 divisors, whose sum is σ = 114003111032208. Its totient is φ = 114003111032206.
The previous prime is 114003111032183. The next prime is 114003111032273. The reversal of 114003111032207 is 702230111300411.
It is a weak prime.
It is an emirp because it is prime and its reverse (702230111300411) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 114003111032207 - 216 = 114003110966671 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (114003111082207) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57001555516103 + 57001555516104.
It is an arithmetic number, because the mean of its divisors is an integer number (57001555516104).
Almost surely, 2114003111032207 is an apocalyptic number.
114003111032207 is a deficient number, since it is larger than the sum of its proper divisors (1).
114003111032207 is an equidigital number, since it uses as much as digits as its factorization.
114003111032207 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1008, while the sum is 26.
Adding to 114003111032207 its reverse (702230111300411), we get a palindrome (816233222332618).
The spelling of 114003111032207 in words is "one hundred fourteen trillion, three billion, one hundred eleven million, thirty-two thousand, two hundred seven".
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