Base | Representation |
---|---|
bin | 1010010111100101011110… |
… | …0000011110010011101001 |
3 | 1111100212012022001110102121 |
4 | 2211321113200132103221 |
5 | 2443240314200142441 |
6 | 40125121500431241 |
7 | 2254434225321103 |
oct | 245712740362351 |
9 | 44325168043377 |
10 | 11400311334121 |
11 | 36a59325a7236 |
12 | 1341559248521 |
13 | 6490773cb068 |
14 | 2b5ac6c1c573 |
15 | 14b83559edd1 |
hex | a5e5781e4e9 |
11400311334121 has 2 divisors, whose sum is σ = 11400311334122. Its totient is φ = 11400311334120.
The previous prime is 11400311334109. The next prime is 11400311334193. The reversal of 11400311334121 is 12143311300411.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 10980972200025 + 419339134096 = 3313755^2 + 647564^2 .
It is a cyclic number.
It is not a de Polignac number, because 11400311334121 - 27 = 11400311333993 is a prime.
It is not a weakly prime, because it can be changed into another prime (11400311338121) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5700155667060 + 5700155667061.
It is an arithmetic number, because the mean of its divisors is an integer number (5700155667061).
Almost surely, 211400311334121 is an apocalyptic number.
It is an amenable number.
11400311334121 is a deficient number, since it is larger than the sum of its proper divisors (1).
11400311334121 is an equidigital number, since it uses as much as digits as its factorization.
11400311334121 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 864, while the sum is 25.
Adding to 11400311334121 its reverse (12143311300411), we get a palindrome (23543622634532).
The spelling of 11400311334121 in words is "eleven trillion, four hundred billion, three hundred eleven million, three hundred thirty-four thousand, one hundred twenty-one".
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