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114004433 is a prime number
BaseRepresentation
bin1101100101110…
…01000111010001
321221112000200102
412302321013101
5213141120213
615151302145
72553010304
oct662710721
9257460612
10114004433
1159397244
123221a955
131a807c5a
14111d8b3b
15a01e158
hex6cb91d1

114004433 has 2 divisors, whose sum is σ = 114004434. Its totient is φ = 114004432.

The previous prime is 114004411. The next prime is 114004441. The reversal of 114004433 is 334400411.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 90307009 + 23697424 = 9503^2 + 4868^2 .

It is a cyclic number.

It is not a de Polignac number, because 114004433 - 26 = 114004369 is a prime.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (114004333) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57002216 + 57002217.

It is an arithmetic number, because the mean of its divisors is an integer number (57002217).

Almost surely, 2114004433 is an apocalyptic number.

It is an amenable number.

114004433 is a deficient number, since it is larger than the sum of its proper divisors (1).

114004433 is an equidigital number, since it uses as much as digits as its factorization.

114004433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 576, while the sum is 20.

The square root of 114004433 is about 10677.2858442584. The cubic root of 114004433 is about 484.8870435212.

Adding to 114004433 its reverse (334400411), we get a palindrome (448404844).

The spelling of 114004433 in words is "one hundred fourteen million, four thousand, four hundred thirty-three".