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114010412353 is a prime number
BaseRepresentation
bin110101000101110001…
…1001101010101000001
3101220021120201000212221
41222023203031111001
53331443131143403
6124213050451041
711144166341515
oct1521343152501
9356246630787
10114010412353
11443959a6292
121a119a33a81
13a99c325a76
145737a88145
152e74227dbd
hex1a8b8cd541

114010412353 has 2 divisors, whose sum is σ = 114010412354. Its totient is φ = 114010412352.

The previous prime is 114010412311. The next prime is 114010412357. The reversal of 114010412353 is 353214010411.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 70305583104 + 43704829249 = 265152^2 + 209057^2 .

It is a cyclic number.

It is not a de Polignac number, because 114010412353 - 213 = 114010404161 is a prime.

It is not a weakly prime, because it can be changed into another prime (114010412357) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57005206176 + 57005206177.

It is an arithmetic number, because the mean of its divisors is an integer number (57005206177).

Almost surely, 2114010412353 is an apocalyptic number.

It is an amenable number.

114010412353 is a deficient number, since it is larger than the sum of its proper divisors (1).

114010412353 is an equidigital number, since it uses as much as digits as its factorization.

114010412353 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1440, while the sum is 25.

Adding to 114010412353 its reverse (353214010411), we get a palindrome (467224422764).

The spelling of 114010412353 in words is "one hundred fourteen billion, ten million, four hundred twelve thousand, three hundred fifty-three".