Base | Representation |
---|---|
bin | 11001111011000100011111… |
… | …011011010101000001101111 |
3 | 112221200021212011220012121122 |
4 | 121323010133123111001233 |
5 | 104420421332114130111 |
6 | 1042251400445251155 |
7 | 33004660561256105 |
oct | 3173043733250157 |
9 | 487607764805548 |
10 | 114010434130031 |
11 | 3336660a90311a |
12 | 10953b9b863abb |
13 | 4b801a39b871a |
14 | 20221c4d2dc75 |
15 | d2aa16731cdb |
hex | 67b11f6d506f |
114010434130031 has 2 divisors, whose sum is σ = 114010434130032. Its totient is φ = 114010434130030.
The previous prime is 114010434130027. The next prime is 114010434130169. The reversal of 114010434130031 is 130031434010411.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 114010434130031 - 22 = 114010434130027 is a prime.
It is a super-2 number, since 2×1140104341300312 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (114010434130001) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57005217065015 + 57005217065016.
It is an arithmetic number, because the mean of its divisors is an integer number (57005217065016).
Almost surely, 2114010434130031 is an apocalyptic number.
114010434130031 is a deficient number, since it is larger than the sum of its proper divisors (1).
114010434130031 is an equidigital number, since it uses as much as digits as its factorization.
114010434130031 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1728, while the sum is 26.
Adding to 114010434130031 its reverse (130031434010411), we get a palindrome (244041868140442).
The spelling of 114010434130031 in words is "one hundred fourteen trillion, ten billion, four hundred thirty-four million, one hundred thirty thousand, thirty-one".
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