114010541013433 has 2 divisors, whose sum is σ = 114010541013434. Its totient is φ = 114010541013432.

The previous prime is 114010541013431. The next prime is 114010541013487. The reversal of 114010541013433 is 334310145010411.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 97889890420624 + 16120650592809 = 9893932^2 + 4015053^2 .

It is an emirp because it is prime and its reverse (334310145010411) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 114010541013433 - 2¹ = 114010541013431 is a prime.

Together with 114010541013431, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 114010541013395 and 114010541013404.

It is not a weakly prime, because it can be changed into another prime (114010541013431) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57005270506716 + 57005270506717.

It is an arithmetic number, because the mean of its divisors is an integer number (57005270506717).

Almost surely, 2^{114010541013433} is an apocalyptic number.

It is an amenable number.

114010541013433 is a deficient number, since it is larger than the sum of its proper divisors (1).

114010541013433 is an equidigital number, since it uses as much as digits as its factorization.

114010541013433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 8640, while the sum is 31.

Adding to 114010541013433 its reverse (334310145010411), we get a palindrome (448320686023844).

The spelling of 114010541013433 in words is "one hundred fourteen trillion, ten billion, five hundred forty-one million, thirteen thousand, four hundred thirty-three".