Base | Representation |
---|---|
bin | 100001111110100… |
… | …1011001011100101 |
3 | 2221110022120222021 |
4 | 1003331023023211 |
5 | 4313332010203 |
6 | 305044303141 |
7 | 40152530005 |
oct | 10375131345 |
9 | 2843276867 |
10 | 1140110053 |
11 | 535620615 |
12 | 2799a1ab1 |
13 | 152285644 |
14 | ab5c0005 |
15 | 6a15a5bd |
hex | 43f4b2e5 |
1140110053 has 2 divisors, whose sum is σ = 1140110054. Its totient is φ = 1140110052.
The previous prime is 1140110039. The next prime is 1140110057. The reversal of 1140110053 is 3500110411.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 986399649 + 153710404 = 31407^2 + 12398^2 .
It is a cyclic number.
It is not a de Polignac number, because 1140110053 - 29 = 1140109541 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1140110057) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 570055026 + 570055027.
It is an arithmetic number, because the mean of its divisors is an integer number (570055027).
Almost surely, 21140110053 is an apocalyptic number.
It is an amenable number.
1140110053 is a deficient number, since it is larger than the sum of its proper divisors (1).
1140110053 is an equidigital number, since it uses as much as digits as its factorization.
1140110053 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 60, while the sum is 16.
The square root of 1140110053 is about 33765.5157372133. The cubic root of 1140110053 is about 1044.6775415880.
Adding to 1140110053 its reverse (3500110411), we get a palindrome (4640220464).
The spelling of 1140110053 in words is "one billion, one hundred forty million, one hundred ten thousand, fifty-three".
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