Base | Representation |
---|---|
bin | 110101000101110011… |
… | …0111111011011110011 |
3 | 101220021122120102012022 |
4 | 1222023212333123303 |
5 | 3331443404412034 |
6 | 124213124022055 |
7 | 11144210641622 |
oct | 1521346773363 |
9 | 356248512168 |
10 | 114011404019 |
11 | 44396513347 |
12 | 1a11a23192b |
13 | a99c5b2256 |
14 | 5737c656b9 |
15 | 2e74371b2e |
hex | 1a8b9bf6f3 |
114011404019 has 2 divisors, whose sum is σ = 114011404020. Its totient is φ = 114011404018.
The previous prime is 114011403953. The next prime is 114011404021. The reversal of 114011404019 is 910404110411.
It is a strong prime.
It is an emirp because it is prime and its reverse (910404110411) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 114011404019 - 224 = 113994626803 is a prime.
It is a super-2 number, since 2×1140114040192 (a number of 23 digits) contains 22 as substring.
Together with 114011404021, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (114011404069) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57005702009 + 57005702010.
It is an arithmetic number, because the mean of its divisors is an integer number (57005702010).
Almost surely, 2114011404019 is an apocalyptic number.
114011404019 is a deficient number, since it is larger than the sum of its proper divisors (1).
114011404019 is an equidigital number, since it uses as much as digits as its factorization.
114011404019 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 576, while the sum is 26.
The spelling of 114011404019 in words is "one hundred fourteen billion, eleven million, four hundred four thousand, nineteen".
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