Base | Representation |
---|---|
bin | 10000100101110100000… |
… | …110001011011111100101 |
3 | 11000222211111211201022201 |
4 | 100211310012023133211 |
5 | 122134423203013222 |
6 | 2231432230054501 |
7 | 145241043016561 |
oct | 20456406133745 |
9 | 4028744751281 |
10 | 1140114110437 |
11 | 3aa579768985 |
12 | 164b65aaa431 |
13 | 836876a1ab3 |
14 | 3d278c9a6a1 |
15 | 1e9cc4c8427 |
hex | 1097418b7e5 |
1140114110437 has 2 divisors, whose sum is σ = 1140114110438. Its totient is φ = 1140114110436.
The previous prime is 1140114110411. The next prime is 1140114110483. The reversal of 1140114110437 is 7340114110411.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1048154154436 + 91959956001 = 1023794^2 + 303249^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1140114110437 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1140114410437) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 570057055218 + 570057055219.
It is an arithmetic number, because the mean of its divisors is an integer number (570057055219).
Almost surely, 21140114110437 is an apocalyptic number.
It is an amenable number.
1140114110437 is a deficient number, since it is larger than the sum of its proper divisors (1).
1140114110437 is an equidigital number, since it uses as much as digits as its factorization.
1140114110437 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1344, while the sum is 28.
Adding to 1140114110437 its reverse (7340114110411), we get a palindrome (8480228220848).
The spelling of 1140114110437 in words is "one trillion, one hundred forty billion, one hundred fourteen million, one hundred ten thousand, four hundred thirty-seven".
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