1140121 has 2 divisors, whose sum is σ = 1140122. Its totient is φ = 1140120.

The previous prime is 1140103. The next prime is 1140127. The reversal of 1140121 is 1210411.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1125721 + 14400 = 1061^2 + 120^2 .

It is an emirp because it is prime and its reverse (1210411) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1140121 - 2⁷ = 1139993 is a prime.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 1140098 and 1140107.

It is not a weakly prime, because it can be changed into another prime (1140127) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 570060 + 570061.

It is an arithmetic number, because the mean of its divisors is an integer number (570061).

2^1140121 is an apocalyptic number.

It is an amenable number.

1140121 is a deficient number, since it is larger than the sum of its proper divisors (1).

1140121 is an equidigital number, since it uses as much as digits as its factorization.

1140121 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 8, while the sum is 10.

The square root of 1140121 is about 1067.7644871412. The cubic root of 1140121 is about 104.4680885139.

Adding to 1140121 its reverse (1210411), we get a palindrome (2350532).

The spelling of 1140121 in words is "one million, one hundred forty thousand, one hundred twenty-one".