114012413 has 4 divisors (see below), whose sum is σ = 114034368. Its totient is φ = 113990460.

The previous prime is 114012401. The next prime is 114012419. The reversal of 114012413 is 314210411.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 314210411 = 521 ⋅603091.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-114012413 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 114012391 and 114012400.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (114012419) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1670 + ... + 15192.

It is an arithmetic number, because the mean of its divisors is an integer number (28508592).

Almost surely, 2^114012413 is an apocalyptic number.

It is an amenable number.

114012413 is a deficient number, since it is larger than the sum of its proper divisors (21955).

114012413 is an equidigital number, since it uses as much as digits as its factorization.

114012413 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 21954.

The product of its (nonzero) digits is 96, while the sum is 17.

The square root of 114012413 is about 10677.6595281925. The cubic root of 114012413 is about 484.8983568484.

Adding to 114012413 its reverse (314210411), we get a palindrome (428222824).

The spelling of 114012413 in words is "one hundred fourteen million, twelve thousand, four hundred thirteen".