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1140132402313 is a prime number
BaseRepresentation
bin10000100101110101001…
…011111101010010001001
311000222212210021001001121
4100211311023331102021
5122134442343333223
62231434122115241
7145241354342632
oct20456513752211
94028783231047
101140132402313
113aa589021933
12164b7004bb21
138368b4078a8
143d27b49c889
151e9cdddd15d
hex109752fd489

1140132402313 has 2 divisors, whose sum is σ = 1140132402314. Its totient is φ = 1140132402312.

The previous prime is 1140132402271. The next prime is 1140132402323. The reversal of 1140132402313 is 3132042310411.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 641798061129 + 498334341184 = 801123^2 + 705928^2 .

It is a cyclic number.

It is not a de Polignac number, because 1140132402313 - 217 = 1140132271241 is a prime.

It is not a weakly prime, because it can be changed into another prime (1140132402323) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 570066201156 + 570066201157.

It is an arithmetic number, because the mean of its divisors is an integer number (570066201157).

Almost surely, 21140132402313 is an apocalyptic number.

It is an amenable number.

1140132402313 is a deficient number, since it is larger than the sum of its proper divisors (1).

1140132402313 is an equidigital number, since it uses as much as digits as its factorization.

1140132402313 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 1140132402313 its reverse (3132042310411), we get a palindrome (4272174712724).

The spelling of 1140132402313 in words is "one trillion, one hundred forty billion, one hundred thirty-two million, four hundred two thousand, three hundred thirteen".