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114013420451407 is a prime number
BaseRepresentation
bin11001111011000111010001…
…011011001111011001001111
3112221200120120022012001102001
4121323013101123033121033
5104420443441113421112
61042253013044413131
733005124562501321
oct3173072133173117
9487616508161361
10114013420451407
1133367902580614
12109546939a71a7
134b8055b5c0ba9
1420223c97b5611
15d2ab3d9c2c57
hex67b1d16cf64f

114013420451407 has 2 divisors, whose sum is σ = 114013420451408. Its totient is φ = 114013420451406.

The previous prime is 114013420451353. The next prime is 114013420451459. The reversal of 114013420451407 is 704154024310411.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 114013420451407 - 223 = 114013412062799 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (114013420451107) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57006710225703 + 57006710225704.

It is an arithmetic number, because the mean of its divisors is an integer number (57006710225704).

Almost surely, 2114013420451407 is an apocalyptic number.

114013420451407 is a deficient number, since it is larger than the sum of its proper divisors (1).

114013420451407 is an equidigital number, since it uses as much as digits as its factorization.

114013420451407 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 53760, while the sum is 37.

Adding to 114013420451407 its reverse (704154024310411), we get a palindrome (818167444761818).

The spelling of 114013420451407 in words is "one hundred fourteen trillion, thirteen billion, four hundred twenty million, four hundred fifty-one thousand, four hundred seven".