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11401444113142 = 217335336591563
BaseRepresentation
bin1010010111101001101100…
…0001101011101011110110
31111100222010020120121010011
42211322123001223223312
52443300124143110032
640125430124050434
72254504261635616
oct245723301535366
944328106517104
1011401444113142
1136a6363a6a946
121341814693a1a
136491c7cb78c5
142b5b93450a46
1514b89ec5d247
hexa5e9b06baf6

11401444113142 has 8 divisors (see below), whose sum is σ = 18108175944456. Its totient is φ = 5365385464992.

The previous prime is 11401444113139. The next prime is 11401444113161. The reversal of 11401444113142 is 24131144410411.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a super-2 number, since 2×114014441131422 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 167668295748 + ... + 167668295815.

It is an arithmetic number, because the mean of its divisors is an integer number (2263521993057).

Almost surely, 211401444113142 is an apocalyptic number.

11401444113142 is a deficient number, since it is larger than the sum of its proper divisors (6706731831314).

11401444113142 is a wasteful number, since it uses less digits than its factorization.

11401444113142 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 335336591582.

The product of its (nonzero) digits is 6144, while the sum is 31.

Adding to 11401444113142 its reverse (24131144410411), we get a palindrome (35532588523553).

The spelling of 11401444113142 in words is "eleven trillion, four hundred one billion, four hundred forty-four million, one hundred thirteen thousand, one hundred forty-two".

Divisors: 1 2 17 34 335336591563 670673183126 5700722056571 11401444113142