1140187133 has 2 divisors, whose sum is σ = 1140187134. Its totient is φ = 1140187132.

The previous prime is 1140187129. The next prime is 1140187141. The reversal of 1140187133 is 3317810411.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 874562329 + 265624804 = 29573^2 + 16298^2 .

It is an emirp because it is prime and its reverse (3317810411) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1140187133 - 2² = 1140187129 is a prime.

It is a super-3 number, since 3×1140187133³ (a number of 28 digits) contains 333 as substring.

It is a Sophie Germain prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 1140187096 and 1140187105.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1140187033) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 570093566 + 570093567.

It is an arithmetic number, because the mean of its divisors is an integer number (570093567).

Almost surely, 2^1140187133 is an apocalyptic number.

It is an amenable number.

1140187133 is a deficient number, since it is larger than the sum of its proper divisors (1).

1140187133 is an equidigital number, since it uses as much as digits as its factorization.

1140187133 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2016, while the sum is 29.

The square root of 1140187133 is about 33766.6571191168. The cubic root of 1140187133 is about 1044.7010837394.

Adding to 1140187133 its reverse (3317810411), we get a palindrome (4457997544).

The spelling of 1140187133 in words is "one billion, one hundred forty million, one hundred eighty-seven thousand, one hundred thirty-three".