11402034013033 has 2 divisors, whose sum is σ = 11402034013034. Its totient is φ = 11402034013032.

The previous prime is 11402034012983. The next prime is 11402034013127. The reversal of 11402034013033 is 33031043020411.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11081255637904 + 320778375129 = 3328852^2 + 566373^2 .

It is a cyclic number.

It is not a de Polignac number, because 11402034013033 - 2²¹ = 11402031915881 is a prime.

It is a super-2 number, since 2×11402034013033² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11402034012989 and 11402034013007.

It is not a weakly prime, because it can be changed into another prime (11402034113033) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5701017006516 + 5701017006517.

It is an arithmetic number, because the mean of its divisors is an integer number (5701017006517).

Almost surely, 2^{11402034013033} is an apocalyptic number.

It is an amenable number.

11402034013033 is a deficient number, since it is larger than the sum of its proper divisors (1).

11402034013033 is an equidigital number, since it uses as much as digits as its factorization.

11402034013033 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 11402034013033 its reverse (33031043020411), we get a palindrome (44433077033444).

The spelling of 11402034013033 in words is "eleven trillion, four hundred two billion, thirty-four million, thirteen thousand, thirty-three".