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114020400493 is a prime number
BaseRepresentation
bin110101000110000100…
…1010011110101101101
3101220022021111111001001
41222030021103311231
53332003210303433
6124214044520301
711144350261456
oct1521411236555
9356267444031
10114020400493
11443a05a854a
121a121250091
13a9a14120cc
14573912812d
152e7504c57d
hex1a8c253d6d

114020400493 has 2 divisors, whose sum is σ = 114020400494. Its totient is φ = 114020400492.

The previous prime is 114020400421. The next prime is 114020400497. The reversal of 114020400493 is 394004020411.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 73547812809 + 40472587684 = 271197^2 + 201178^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-114020400493 is a prime.

It is a super-2 number, since 2×1140204004932 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (114020400497) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57010200246 + 57010200247.

It is an arithmetic number, because the mean of its divisors is an integer number (57010200247).

Almost surely, 2114020400493 is an apocalyptic number.

It is an amenable number.

114020400493 is a deficient number, since it is larger than the sum of its proper divisors (1).

114020400493 is an equidigital number, since it uses as much as digits as its factorization.

114020400493 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3456, while the sum is 28.

The spelling of 114020400493 in words is "one hundred fourteen billion, twenty million, four hundred thousand, four hundred ninety-three".