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11402113013 is a prime number
BaseRepresentation
bin10101001111001111…
…00110111111110101
31002102122002100120222
422213213212333311
5141322420104023
65123230504125
7552361234664
oct124747467765
932378070528
1011402113013
1149212172a5
122262665045
1310c9328945
147a2464ddb
1546b01dcc8
hex2a79e6ff5

11402113013 has 2 divisors, whose sum is σ = 11402113014. Its totient is φ = 11402113012.

The previous prime is 11402113001. The next prime is 11402113033. The reversal of 11402113013 is 31031120411.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11274829489 + 127283524 = 106183^2 + 11282^2 .

It is a cyclic number.

It is not a de Polignac number, because 11402113013 - 210 = 11402111989 is a prime.

It is a super-2 number, since 2×114021130132 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11402112982 and 11402113000.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11402113033) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5701056506 + 5701056507.

It is an arithmetic number, because the mean of its divisors is an integer number (5701056507).

Almost surely, 211402113013 is an apocalyptic number.

It is an amenable number.

11402113013 is a deficient number, since it is larger than the sum of its proper divisors (1).

11402113013 is an equidigital number, since it uses as much as digits as its factorization.

11402113013 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 11402113013 its reverse (31031120411), we get a palindrome (42433233424).

The spelling of 11402113013 in words is "eleven billion, four hundred two million, one hundred thirteen thousand, thirteen".