Base | Representation |
---|---|
bin | 10101001111001111… |
… | …00111100000111010 |
3 | 1002102122002110111101 |
4 | 22213213213200322 |
5 | 141322420141010 |
6 | 5123230522014 |
7 | 552361244110 |
oct | 124747474072 |
9 | 32378073441 |
10 | 11402115130 |
11 | 492121894a |
12 | 226266630a |
13 | 10c93298b3 |
14 | 7a2465ab0 |
15 | 46b01e73a |
hex | 2a79e783a |
11402115130 has 32 divisors (see below), whose sum is σ = 23459746176. Its totient is φ = 3908635584.
The previous prime is 11402115097. The next prime is 11402115143. The reversal of 11402115130 is 3151120411.
It is a junction number, because it is equal to n+sod(n) for n = 11402115098 and 11402115107.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 592317 + ... + 611263.
It is an arithmetic number, because the mean of its divisors is an integer number (733117068).
Almost surely, 211402115130 is an apocalyptic number.
11402115130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
11402115130 is an abundant number, since it is smaller than the sum of its proper divisors (12057631046).
11402115130 is a wasteful number, since it uses less digits than its factorization.
11402115130 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 27558.
The product of its (nonzero) digits is 120, while the sum is 19.
Adding to 11402115130 its reverse (3151120411), we get a palindrome (14553235541).
It can be divided in two parts, 1140211 and 5130, that added together give a triangular number (1145341 = T1513).
The spelling of 11402115130 in words is "eleven billion, four hundred two million, one hundred fifteen thousand, one hundred thirty".
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