Base | Representation |
---|---|
bin | 10000100101111001111… |
… | …100111010010011000011 |
3 | 11001000002100200111102221 |
4 | 100211321330322103003 |
5 | 122140123330002003 |
6 | 2231450055351511 |
7 | 145243345004035 |
oct | 20457174722303 |
9 | 4030070614387 |
10 | 1140212344003 |
11 | 3aa61a163247 |
12 | 164b92982597 |
13 | 836a1b47575 |
14 | 3d287d4bc55 |
15 | 1e9d5e2e7bd |
hex | 10979f3a4c3 |
1140212344003 has 2 divisors, whose sum is σ = 1140212344004. Its totient is φ = 1140212344002.
The previous prime is 1140212343973. The next prime is 1140212344027. The reversal of 1140212344003 is 3004432120411.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1140212344003 is a prime.
It is a super-2 number, since 2×11402123440032 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1140212144003) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 570106172001 + 570106172002.
It is an arithmetic number, because the mean of its divisors is an integer number (570106172002).
Almost surely, 21140212344003 is an apocalyptic number.
1140212344003 is a deficient number, since it is larger than the sum of its proper divisors (1).
1140212344003 is an equidigital number, since it uses as much as digits as its factorization.
1140212344003 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 1140212344003 its reverse (3004432120411), we get a palindrome (4144644464414).
The spelling of 1140212344003 in words is "one trillion, one hundred forty billion, two hundred twelve million, three hundred forty-four thousand, three".
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