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114021413351 is a prime number
BaseRepresentation
bin110101000110000110…
…1001011000111100111
3101220022100101221102022
41222030031023013213
53332003440211401
6124214122333355
711144362010426
oct1521415130747
9356270357368
10114021413351
11443a112a51a
121a12165a25b
13a9a16a8131
14573930d2bd
152e7519c71b
hex1a8c34b1e7

114021413351 has 2 divisors, whose sum is σ = 114021413352. Its totient is φ = 114021413350.

The previous prime is 114021413347. The next prime is 114021413357. The reversal of 114021413351 is 153314120411.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 114021413351 - 22 = 114021413347 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 114021413351.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (114021413357) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57010706675 + 57010706676.

It is an arithmetic number, because the mean of its divisors is an integer number (57010706676).

Almost surely, 2114021413351 is an apocalyptic number.

114021413351 is a deficient number, since it is larger than the sum of its proper divisors (1).

114021413351 is an equidigital number, since it uses as much as digits as its factorization.

114021413351 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1440, while the sum is 26.

Adding to 114021413351 its reverse (153314120411), we get a palindrome (267335533762).

The spelling of 114021413351 in words is "one hundred fourteen billion, twenty-one million, four hundred thirteen thousand, three hundred fifty-one".