Base | Representation |
---|---|
bin | 10101001111010000… |
… | …00110110101001001 |
3 | 1002102122022222110011 |
4 | 22213220012311021 |
5 | 141322433242101 |
6 | 5123233351521 |
7 | 552362320063 |
oct | 124750066511 |
9 | 32378288404 |
10 | 11402243401 |
11 | 49212a625a |
12 | 22627085a1 |
13 | 10c93730b3 |
14 | 7a249a733 |
15 | 46b047751 |
hex | 2a7a06d49 |
11402243401 has 2 divisors, whose sum is σ = 11402243402. Its totient is φ = 11402243400.
The previous prime is 11402243389. The next prime is 11402243443. The reversal of 11402243401 is 10434220411.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 9197001801 + 2205241600 = 95901^2 + 46960^2 .
It is a cyclic number.
It is not a de Polignac number, because 11402243401 - 221 = 11400146249 is a prime.
It is a super-2 number, since 2×114022434012 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (11402243471) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5701121700 + 5701121701.
It is an arithmetic number, because the mean of its divisors is an integer number (5701121701).
Almost surely, 211402243401 is an apocalyptic number.
It is an amenable number.
11402243401 is a deficient number, since it is larger than the sum of its proper divisors (1).
11402243401 is an equidigital number, since it uses as much as digits as its factorization.
11402243401 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 768, while the sum is 22.
Adding to 11402243401 its reverse (10434220411), we get a palindrome (21836463812).
The spelling of 11402243401 in words is "eleven billion, four hundred two million, two hundred forty-three thousand, four hundred one".
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