1140224433133 has 2 divisors, whose sum is σ = 1140224433134. Its totient is φ = 1140224433132.

The previous prime is 1140224433113. The next prime is 1140224433193. The reversal of 1140224433133 is 3313344220411.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1033205162089 + 107019271044 = 1016467^2 + 327138^2 .

It is a cyclic number.

It is not a de Polignac number, because 1140224433133 - 2²¹ = 1140222335981 is a prime.

It is a super-2 number, since 2×1140224433133² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1140224433095 and 1140224433104.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1140224433113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 570112216566 + 570112216567.

It is an arithmetic number, because the mean of its divisors is an integer number (570112216567).

Almost surely, 2^{1140224433133} is an apocalyptic number.

It is an amenable number.

1140224433133 is a deficient number, since it is larger than the sum of its proper divisors (1).

1140224433133 is an equidigital number, since it uses as much as digits as its factorization.

1140224433133 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 20736, while the sum is 31.

Adding to 1140224433133 its reverse (3313344220411), we get a palindrome (4453568653544).

The spelling of 1140224433133 in words is "one trillion, one hundred forty billion, two hundred twenty-four million, four hundred thirty-three thousand, one hundred thirty-three".