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11402264141 is a prime number
BaseRepresentation
bin10101001111010000…
…01011111001001101
31002102122101000220022
422213220023321031
5141322434423031
65123234031525
7552362434412
oct124750137115
932378330808
1011402264141
11492130a8a4
1222627185a5
1310c937c678
147a24a4109
1546b04d97b
hex2a7a0be4d

11402264141 has 2 divisors, whose sum is σ = 11402264142. Its totient is φ = 11402264140.

The previous prime is 11402264129. The next prime is 11402264147. The reversal of 11402264141 is 14146220411.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9054474025 + 2347790116 = 95155^2 + 48454^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11402264141 is a prime.

It is a super-2 number, since 2×114022641412 (a number of 21 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 11402264141.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11402264147) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5701132070 + 5701132071.

It is an arithmetic number, because the mean of its divisors is an integer number (5701132071).

Almost surely, 211402264141 is an apocalyptic number.

It is an amenable number.

11402264141 is a deficient number, since it is larger than the sum of its proper divisors (1).

11402264141 is an equidigital number, since it uses as much as digits as its factorization.

11402264141 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1536, while the sum is 26.

Adding to 11402264141 its reverse (14146220411), we get a palindrome (25548484552).

The spelling of 11402264141 in words is "eleven billion, four hundred two million, two hundred sixty-four thousand, one hundred forty-one".