Base | Representation |
---|---|
bin | 110101000110001000… |
… | …1111010101001100101 |
3 | 101220022102202002212001 |
4 | 1222030101322221211 |
5 | 3332004300002423 |
6 | 124214205125301 |
7 | 11144405406205 |
oct | 1521421725145 |
9 | 356272662761 |
10 | 114022656613 |
11 | 443a18a9608 |
12 | 1a121b59831 |
13 | a9a1a21ca8 |
14 | 5739554405 |
15 | 2e75345cad |
hex | 1a8c47aa65 |
114022656613 has 2 divisors, whose sum is σ = 114022656614. Its totient is φ = 114022656612.
The previous prime is 114022656551. The next prime is 114022656641. The reversal of 114022656613 is 316656220411.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 105389831044 + 8632825569 = 324638^2 + 92913^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-114022656613 is a prime.
It is a super-2 number, since 2×1140226566132 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (114022659613) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57011328306 + 57011328307.
It is an arithmetic number, because the mean of its divisors is an integer number (57011328307).
Almost surely, 2114022656613 is an apocalyptic number.
It is an amenable number.
114022656613 is a deficient number, since it is larger than the sum of its proper divisors (1).
114022656613 is an equidigital number, since it uses as much as digits as its factorization.
114022656613 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 51840, while the sum is 37.
The spelling of 114022656613 in words is "one hundred fourteen billion, twenty-two million, six hundred fifty-six thousand, six hundred thirteen".
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