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114023243522417 is a prime number
BaseRepresentation
bin11001111011010000011010…
…111011010010000101110001
3112221201111220220000202120212
4121323100122323102011301
5104421124100320204132
61042301315511113505
733005623161305315
oct3173203273220561
9487644826022525
10114023243522417
1133370a93430219
1210956575672895
134b81465741248
142022a7c23db45
15d2b0160825b2
hex67b41aed2171

114023243522417 has 2 divisors, whose sum is σ = 114023243522418. Its totient is φ = 114023243522416.

The previous prime is 114023243522407. The next prime is 114023243522471. The reversal of 114023243522417 is 714225342320411.

Together with next prime (114023243522471) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 114022908778801 + 334743616 = 10678151^2 + 18296^2 .

It is a cyclic number.

It is not a de Polignac number, because 114023243522417 - 218 = 114023243260273 is a prime.

It is not a weakly prime, because it can be changed into another prime (114023243522407) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57011621761208 + 57011621761209.

It is an arithmetic number, because the mean of its divisors is an integer number (57011621761209).

Almost surely, 2114023243522417 is an apocalyptic number.

It is an amenable number.

114023243522417 is a deficient number, since it is larger than the sum of its proper divisors (1).

114023243522417 is an equidigital number, since it uses as much as digits as its factorization.

114023243522417 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 322560, while the sum is 41.

Adding to 114023243522417 its reverse (714225342320411), we get a palindrome (828248585842828).

The spelling of 114023243522417 in words is "one hundred fourteen trillion, twenty-three billion, two hundred forty-three million, five hundred twenty-two thousand, four hundred seventeen".