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114023243522407 is a prime number
BaseRepresentation
bin11001111011010000011010…
…111011010010000101100111
3112221201111220220000202120111
4121323100122323102011213
5104421124100320204112
61042301315511113451
733005623161305302
oct3173203273220547
9487644826022514
10114023243522407
1133370a9343020a
1210956575672887
134b8146574123b
142022a7c23db39
15d2b0160825a7
hex67b41aed2167

114023243522407 has 2 divisors, whose sum is σ = 114023243522408. Its totient is φ = 114023243522406.

The previous prime is 114023243522369. The next prime is 114023243522417. The reversal of 114023243522407 is 704225342320411.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-114023243522407 is a prime.

It is a super-2 number, since 2×1140232435224072 (a number of 29 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 114023243522407.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (114023243522417) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57011621761203 + 57011621761204.

It is an arithmetic number, because the mean of its divisors is an integer number (57011621761204).

Almost surely, 2114023243522407 is an apocalyptic number.

114023243522407 is a deficient number, since it is larger than the sum of its proper divisors (1).

114023243522407 is an equidigital number, since it uses as much as digits as its factorization.

114023243522407 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 322560, while the sum is 40.

Adding to 114023243522407 its reverse (704225342320411), we get a palindrome (818248585842818).

The spelling of 114023243522407 in words is "one hundred fourteen trillion, twenty-three billion, two hundred forty-three million, five hundred twenty-two thousand, four hundred seven".