Base | Representation |
---|---|
bin | 11001111011010001101000… |
… | …111000000110101100011111 |
3 | 112221201122022000212100211222 |
4 | 121323101220320012230133 |
5 | 104421134240113442114 |
6 | 1042302053345403555 |
7 | 33006000451321355 |
oct | 3173215070065437 |
9 | 487648260770758 |
10 | 114024551312159 |
11 | 333715a4668a94 |
12 | 1095687b6395bb |
13 | 4b81613675a27 |
14 | 2022b63bcb7d5 |
15 | d2b090cb098e |
hex | 67b468e06b1f |
114024551312159 has 2 divisors, whose sum is σ = 114024551312160. Its totient is φ = 114024551312158.
The previous prime is 114024551312101. The next prime is 114024551312167. The reversal of 114024551312159 is 951213155420411.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 114024551312159 - 220 = 114024550263583 is a prime.
It is a super-2 number, since 2×1140245513121592 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (114024551311159) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57012275656079 + 57012275656080.
It is an arithmetic number, because the mean of its divisors is an integer number (57012275656080).
Almost surely, 2114024551312159 is an apocalyptic number.
114024551312159 is a deficient number, since it is larger than the sum of its proper divisors (1).
114024551312159 is an equidigital number, since it uses as much as digits as its factorization.
114024551312159 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 216000, while the sum is 44.
The spelling of 114024551312159 in words is "one hundred fourteen trillion, twenty-four billion, five hundred fifty-one million, three hundred twelve thousand, one hundred fifty-nine".
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