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1140301431310 = 25143979242629
BaseRepresentation
bin10000100101111111010…
…000110000001000001110
311001000022120022121020211
4100211333100300020032
5122140314131300220
62231503001033034
7145245506145556
oct20457720601016
94030276277224
101140301431310
113aa665480918
12164bb878577a
13836b7439c52
143d295adc166
151e9ddb7ab5a
hex1097f43020e

1140301431310 has 16 divisors (see below), whose sum is σ = 2053968969600. Its totient is φ = 455803596256.

The previous prime is 1140301431253. The next prime is 1140301431329. The reversal of 1140301431310 is 131341030411.

It is a super-2 number, since 2×11403014313102 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 39606925 + ... + 39635704.

It is an arithmetic number, because the mean of its divisors is an integer number (128373060600).

Almost surely, 21140301431310 is an apocalyptic number.

1140301431310 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

1140301431310 is a deficient number, since it is larger than the sum of its proper divisors (913667538290).

1140301431310 is a wasteful number, since it uses less digits than its factorization.

1140301431310 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 79244075.

The product of its (nonzero) digits is 432, while the sum is 22.

Adding to 1140301431310 its reverse (131341030411), we get a palindrome (1271642461721).

The spelling of 1140301431310 in words is "one trillion, one hundred forty billion, three hundred one million, four hundred thirty-one thousand, three hundred ten".

Divisors: 1 2 5 10 1439 2878 7195 14390 79242629 158485258 396213145 792426290 114030143131 228060286262 570150715655 1140301431310