Base | Representation |
---|---|
bin | 11001111011010111000101… |
… | …100111101010100110011111 |
3 | 112221202012101210102212021201 |
4 | 121323113011213222212133 |
5 | 104421233230434014132 |
6 | 1042304502115340331 |
7 | 33006265445430523 |
oct | 3173270547524637 |
9 | 487665353385251 |
10 | 114030402251167 |
11 | 33374027339076 |
12 | 10957a32bb16a7 |
13 | 4b820368b110c |
14 | 202315acb7d83 |
15 | d2b2d47a22e7 |
hex | 67b5c59ea99f |
114030402251167 has 2 divisors, whose sum is σ = 114030402251168. Its totient is φ = 114030402251166.
The previous prime is 114030402251137. The next prime is 114030402251257. The reversal of 114030402251167 is 761152204030411.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-114030402251167 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (114030402251137) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57015201125583 + 57015201125584.
It is an arithmetic number, because the mean of its divisors is an integer number (57015201125584).
Almost surely, 2114030402251167 is an apocalyptic number.
114030402251167 is a deficient number, since it is larger than the sum of its proper divisors (1).
114030402251167 is an equidigital number, since it uses as much as digits as its factorization.
114030402251167 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 40320, while the sum is 37.
Adding to 114030402251167 its reverse (761152204030411), we get a palindrome (875182606281578).
The spelling of 114030402251167 in words is "one hundred fourteen trillion, thirty billion, four hundred two million, two hundred fifty-one thousand, one hundred sixty-seven".
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