Base | Representation |
---|---|
bin | 10000100101111111011… |
… | …011110100000111010111 |
3 | 11001000022202202221012000 |
4 | 100211333123310013113 |
5 | 122140320402044343 |
6 | 2231503143130343 |
7 | 145245542614251 |
oct | 20457733640727 |
9 | 4030282687160 |
10 | 1140304331223 |
11 | 3aa667081642 |
12 | 164bb97439b3 |
13 | 836b7c13b85 |
14 | 3d296254cd1 |
15 | 1e9de04eed3 |
hex | 1097f6f41d7 |
1140304331223 has 64 divisors (see below), whose sum is σ = 1756574709120. Its totient is φ = 730513437696.
The previous prime is 1140304331107. The next prime is 1140304331249. The reversal of 1140304331223 is 3221334030411.
It is a happy number.
1140304331223 is a `hidden beast` number, since 1 + 1 + 4 + 0 + 3 + 0 + 433 + 1 + 223 = 666.
It is not a de Polignac number, because 1140304331223 - 217 = 1140304200151 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (27).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1140304331423) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 26940865 + ... + 26983157.
It is an arithmetic number, because the mean of its divisors is an integer number (27446479830).
Almost surely, 21140304331223 is an apocalyptic number.
1140304331223 is a deficient number, since it is larger than the sum of its proper divisors (616270377897).
1140304331223 is a wasteful number, since it uses less digits than its factorization.
1140304331223 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 42673 (or 42667 counting only the distinct ones).
The product of its (nonzero) digits is 5184, while the sum is 27.
Adding to 1140304331223 its reverse (3221334030411), we get a palindrome (4361638361634).
The spelling of 1140304331223 in words is "one trillion, one hundred forty billion, three hundred four million, three hundred thirty-one thousand, two hundred twenty-three".
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