Base | Representation |
---|---|
bin | 10000100101111111011… |
… | …111001000010011110101 |
3 | 11001000022211102002102202 |
4 | 100211333133020103311 |
5 | 122140321112402443 |
6 | 2231503213514245 |
7 | 145245553164233 |
oct | 20457737102365 |
9 | 4030284362382 |
10 | 1140305200373 |
11 | 3aa667615649 |
12 | 164bb9aa2985 |
13 | 836b8159671 |
14 | 3d2963dd953 |
15 | 1e9de1727b8 |
hex | 1097f7c84f5 |
1140305200373 has 2 divisors, whose sum is σ = 1140305200374. Its totient is φ = 1140305200372.
The previous prime is 1140305200369. The next prime is 1140305200453. The reversal of 1140305200373 is 3730025030411.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1098624711409 + 41680488964 = 1048153^2 + 204158^2 .
It is a cyclic number.
It is not a de Polignac number, because 1140305200373 - 22 = 1140305200369 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1140305200273) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 570152600186 + 570152600187.
It is an arithmetic number, because the mean of its divisors is an integer number (570152600187).
Almost surely, 21140305200373 is an apocalyptic number.
It is an amenable number.
1140305200373 is a deficient number, since it is larger than the sum of its proper divisors (1).
1140305200373 is an equidigital number, since it uses as much as digits as its factorization.
1140305200373 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 7560, while the sum is 29.
The spelling of 1140305200373 in words is "one trillion, one hundred forty billion, three hundred five million, two hundred thousand, three hundred seventy-three".
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