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114031312303 is a prime number
BaseRepresentation
bin110101000110011001…
…0111011110110101111
3101220100001000212020011
41222030302323312233
53332014003443203
6124215114434051
711144542106356
oct1521462736657
9356301025204
10114031312303
11443a6780777
121a124a32927
13a9a37629bc
14573a76899d
152e75ea576d
hex1a8ccbbdaf

114031312303 has 2 divisors, whose sum is σ = 114031312304. Its totient is φ = 114031312302.

The previous prime is 114031312261. The next prime is 114031312319. The reversal of 114031312303 is 303213130411.

It is a strong prime.

It is an emirp because it is prime and its reverse (303213130411) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-114031312303 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (114031312393) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57015656151 + 57015656152.

It is an arithmetic number, because the mean of its divisors is an integer number (57015656152).

Almost surely, 2114031312303 is an apocalyptic number.

114031312303 is a deficient number, since it is larger than the sum of its proper divisors (1).

114031312303 is an equidigital number, since it uses as much as digits as its factorization.

114031312303 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 648, while the sum is 22.

Adding to 114031312303 its reverse (303213130411), we get a palindrome (417244442714).

The spelling of 114031312303 in words is "one hundred fourteen billion, thirty-one million, three hundred twelve thousand, three hundred three".