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11403131313301 = 713428929216399
BaseRepresentation
bin1010010111101111111110…
…0101110101110010010101
31111101010110211100020121221
42211323333211311302111
52443312103104011201
640130305354410341
72254564136620540
oct245737745656225
944333424306557
1011403131313301
1136a704a390342
1213420057309b1
136494067020b0
142b5cb3563857
1514b94ce344a1
hexa5eff975c95

11403131313301 has 16 divisors (see below), whose sum is σ = 14037895872000. Its totient is φ = 9020153852928.

The previous prime is 11403131313293. The next prime is 11403131313347. The reversal of 11403131313301 is 10331313130411.

It is a cyclic number.

It is not a de Polignac number, because 11403131313301 - 23 = 11403131313293 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11403131317301) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 14217901 + ... + 14998498.

It is an arithmetic number, because the mean of its divisors is an integer number (877368492000).

Almost surely, 211403131313301 is an apocalyptic number.

It is an amenable number.

11403131313301 is a deficient number, since it is larger than the sum of its proper divisors (2634764558699).

11403131313301 is a wasteful number, since it uses less digits than its factorization.

11403131313301 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 29220708.

The product of its (nonzero) digits is 972, while the sum is 25.

Adding to 11403131313301 its reverse (10331313130411), we get a palindrome (21734444443712).

The spelling of 11403131313301 in words is "eleven trillion, four hundred three billion, one hundred thirty-one million, three hundred thirteen thousand, three hundred one".

Divisors: 1 7 13 91 4289 30023 55757 390299 29216399 204514793 379813187 2658692309 125309135311 877163947177 1629018759043 11403131313301