Base | Representation |
---|---|
bin | 110101000110011001… |
… | …1101110110101110111 |
3 | 101220100001102110200222 |
4 | 1222030303232311313 |
5 | 3332014032134033 |
6 | 124215123124555 |
7 | 11144543636261 |
oct | 1521463566567 |
9 | 356301373628 |
10 | 114031521143 |
11 | 443a6903671 |
12 | 1a124b1375b |
13 | a9a3806a87 |
14 | 573a7c0b31 |
15 | 2e75ee7598 |
hex | 1a8cceed77 |
114031521143 has 2 divisors, whose sum is σ = 114031521144. Its totient is φ = 114031521142.
The previous prime is 114031521113. The next prime is 114031521211. The reversal of 114031521143 is 341125130411.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 114031521143 - 214 = 114031504759 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (114031521113) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57015760571 + 57015760572.
It is an arithmetic number, because the mean of its divisors is an integer number (57015760572).
Almost surely, 2114031521143 is an apocalyptic number.
114031521143 is a deficient number, since it is larger than the sum of its proper divisors (1).
114031521143 is an equidigital number, since it uses as much as digits as its factorization.
114031521143 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1440, while the sum is 26.
Adding to 114031521143 its reverse (341125130411), we get a palindrome (455156651554).
The spelling of 114031521143 in words is "one hundred fourteen billion, thirty-one million, five hundred twenty-one thousand, one hundred forty-three".
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