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11403202209989 is a prime number
BaseRepresentation
bin1010010111110000001111…
…0100010010100011000101
31111101010122202202011121012
42211330003310102203011
52443312224231204424
640130320410132005
72254565660340452
oct245740364224305
944333582664535
1011403202209989
1136a7086404047
121342025421005
136494182c5ab5
142b5cbcb3a829
1514b95428ab0e
hexa5f03d128c5

11403202209989 has 2 divisors, whose sum is σ = 11403202209990. Its totient is φ = 11403202209988.

The previous prime is 11403202209907. The next prime is 11403202210007. The reversal of 11403202209989 is 98990220230411.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 6326945376964 + 5076256833025 = 2515342^2 + 2253055^2 .

It is an emirp because it is prime and its reverse (98990220230411) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11403202209989 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11403202202989) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5701601104994 + 5701601104995.

It is an arithmetic number, because the mean of its divisors is an integer number (5701601104995).

Almost surely, 211403202209989 is an apocalyptic number.

It is an amenable number.

11403202209989 is a deficient number, since it is larger than the sum of its proper divisors (1).

11403202209989 is an equidigital number, since it uses as much as digits as its factorization.

11403202209989 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 559872, while the sum is 50.

The spelling of 11403202209989 in words is "eleven trillion, four hundred three billion, two hundred two million, two hundred nine thousand, nine hundred eighty-nine".