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114032313497 is a prime number
BaseRepresentation
bin110101000110011011…
…0110000010010011001
3101220100002220201121102
41222030312300102121
53332014233012442
6124215152121145
711144553446324
oct1521466602231
9356302821542
10114032313497
11443a72a4a03
121a1252361b5
13a9a3a2361b
14573a9497bb
152e76102232
hex1a8cdb0499

114032313497 has 2 divisors, whose sum is σ = 114032313498. Its totient is φ = 114032313496.

The previous prime is 114032313491. The next prime is 114032313541. The reversal of 114032313497 is 794313230411.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 108090370441 + 5941943056 = 328771^2 + 77084^2 .

It is a cyclic number.

It is not a de Polignac number, because 114032313497 - 210 = 114032312473 is a prime.

It is a super-3 number, since 3×1140323134973 (a number of 34 digits) contains 333 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 114032313497.

It is not a weakly prime, because it can be changed into another prime (114032313491) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57016156748 + 57016156749.

It is an arithmetic number, because the mean of its divisors is an integer number (57016156749).

Almost surely, 2114032313497 is an apocalyptic number.

It is an amenable number.

114032313497 is a deficient number, since it is larger than the sum of its proper divisors (1).

114032313497 is an equidigital number, since it uses as much as digits as its factorization.

114032313497 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 54432, while the sum is 38.

The spelling of 114032313497 in words is "one hundred fourteen billion, thirty-two million, three hundred thirteen thousand, four hundred ninety-seven".