Base | Representation |
---|---|
bin | 1010010111110000100110… |
… | …1001011010000011010001 |
3 | 1111101010220120210110022020 |
4 | 2211330021221122003101 |
5 | 2443312424301123213 |
6 | 40130334222402053 |
7 | 2254601255613216 |
oct | 245741151320321 |
9 | 44333816713266 |
10 | 11403300020433 |
11 | 36a712663a522 |
12 | 1342052130329 |
13 | 649432650ab9 |
14 | 2b5ccbb1bb0d |
15 | 14b95cb5b923 |
hex | a5f09a5a0d1 |
11403300020433 has 32 divisors (see below), whose sum is σ = 15785557332864. Its totient is φ = 7316979651072.
The previous prime is 11403300020419. The next prime is 11403300020443. The reversal of 11403300020433 is 33402000330411.
It is not a de Polignac number, because 11403300020433 - 25 = 11403300020401 is a prime.
It is a super-3 number, since 3×114033000204333 (a number of 40 digits) contains 333 as substring.
It is not an unprimeable number, because it can be changed into a prime (11403300020443) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 9738835 + ... + 10846727.
It is an arithmetic number, because the mean of its divisors is an integer number (493298666652).
Almost surely, 211403300020433 is an apocalyptic number.
It is an amenable number.
11403300020433 is a deficient number, since it is larger than the sum of its proper divisors (4382257312431).
11403300020433 is a wasteful number, since it uses less digits than its factorization.
11403300020433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1109105.
The product of its (nonzero) digits is 2592, while the sum is 24.
Adding to 11403300020433 its reverse (33402000330411), we get a palindrome (44805300350844).
The spelling of 11403300020433 in words is "eleven trillion, four hundred three billion, three hundred million, twenty thousand, four hundred thirty-three".
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