Base | Representation |
---|---|
bin | 10000100110000001000… |
… | …110001010011101001101 |
3 | 11001000101201020022200012 |
4 | 100212001012022131031 |
5 | 122140400021204442 |
6 | 2231510020443005 |
7 | 145246331566421 |
oct | 20460106123515 |
9 | 4030351208605 |
10 | 1140332209997 |
11 | 3aa680893352 |
12 | 165006b49465 |
13 | 836c09254a6 |
14 | 3d299c30b81 |
15 | 1e9e170a582 |
hex | 1098118a74d |
1140332209997 has 2 divisors, whose sum is σ = 1140332209998. Its totient is φ = 1140332209996.
The previous prime is 1140332209967. The next prime is 1140332210123. The reversal of 1140332209997 is 7999022330411.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 943503338281 + 196828871716 = 971341^2 + 443654^2 .
It is a cyclic number.
It is not a de Polignac number, because 1140332209997 - 28 = 1140332209741 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1140332209967) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 570166104998 + 570166104999.
It is an arithmetic number, because the mean of its divisors is an integer number (570166104999).
Almost surely, 21140332209997 is an apocalyptic number.
It is an amenable number.
1140332209997 is a deficient number, since it is larger than the sum of its proper divisors (1).
1140332209997 is an equidigital number, since it uses as much as digits as its factorization.
1140332209997 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 734832, while the sum is 50.
The spelling of 1140332209997 in words is "one trillion, one hundred forty billion, three hundred thirty-two million, two hundred nine thousand, nine hundred ninety-seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.073 sec. • engine limits •