Base | Representation |
---|---|
bin | 10101001111011000… |
… | …10000011100001111 |
3 | 1002102201101020211022 |
4 | 22213230100130033 |
5 | 141323223100333 |
6 | 5123312544355 |
7 | 552404500655 |
oct | 124754203417 |
9 | 32381336738 |
10 | 11403331343 |
11 | 4921979688 |
12 | 2262b520bb |
13 | 10c9664351 |
14 | 7a26a0dd5 |
15 | 46b1aec98 |
hex | 2a7b1070f |
11403331343 has 2 divisors, whose sum is σ = 11403331344. Its totient is φ = 11403331342.
The previous prime is 11403331339. The next prime is 11403331477. The reversal of 11403331343 is 34313330411.
11403331343 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11403331343 - 22 = 11403331339 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11403331843) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5701665671 + 5701665672.
It is an arithmetic number, because the mean of its divisors is an integer number (5701665672).
Almost surely, 211403331343 is an apocalyptic number.
11403331343 is a deficient number, since it is larger than the sum of its proper divisors (1).
11403331343 is an equidigital number, since it uses as much as digits as its factorization.
11403331343 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3888, while the sum is 26.
Adding to 11403331343 its reverse (34313330411), we get a palindrome (45716661754).
The spelling of 11403331343 in words is "eleven billion, four hundred three million, three hundred thirty-one thousand, three hundred forty-three".
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