Base | Representation |
---|---|
bin | 10000100110000001101… |
… | …000000111011010111001 |
3 | 11001000102022222111210212 |
4 | 100212001220013122321 |
5 | 122140404311013312 |
6 | 2231510535320505 |
7 | 145246500336323 |
oct | 20460150073271 |
9 | 4030368874725 |
10 | 1140341110457 |
11 | 3aa6859123aa |
12 | 165009b20135 |
13 | 836c2720733 |
14 | 3d29b0aa613 |
15 | 1e9e23b7822 |
hex | 10981a076b9 |
1140341110457 has 2 divisors, whose sum is σ = 1140341110458. Its totient is φ = 1140341110456.
The previous prime is 1140341110421. The next prime is 1140341110607. The reversal of 1140341110457 is 7540111430411.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1047550203001 + 92790907456 = 1023499^2 + 304616^2 .
It is a cyclic number.
It is not a de Polignac number, because 1140341110457 - 218 = 1140340848313 is a prime.
It is not a weakly prime, because it can be changed into another prime (1140341112457) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 570170555228 + 570170555229.
It is an arithmetic number, because the mean of its divisors is an integer number (570170555229).
Almost surely, 21140341110457 is an apocalyptic number.
It is an amenable number.
1140341110457 is a deficient number, since it is larger than the sum of its proper divisors (1).
1140341110457 is an equidigital number, since it uses as much as digits as its factorization.
1140341110457 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6720, while the sum is 32.
Adding to 1140341110457 its reverse (7540111430411), we get a palindrome (8680452540868).
The spelling of 1140341110457 in words is "one trillion, one hundred forty billion, three hundred forty-one million, one hundred ten thousand, four hundred fifty-seven".
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