1140341131 has 2 divisors, whose sum is σ = 1140341132. Its totient is φ = 1140341130.

The previous prime is 1140341129. The next prime is 1140341141. The reversal of 1140341131 is 1311430411.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1140341131 - 2¹ = 1140341129 is a prime.

It is a super-2 number, since 2×1140341131² = 2600755790100718322, which contains 22 as substring.

Together with 1140341129, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 1140341099 and 1140341108.

It is not a weakly prime, because it can be changed into another prime (1140341141) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 570170565 + 570170566.

It is an arithmetic number, because the mean of its divisors is an integer number (570170566).

Almost surely, 2^1140341131 is an apocalyptic number.

1140341131 is a deficient number, since it is larger than the sum of its proper divisors (1).

1140341131 is an equidigital number, since it uses as much as digits as its factorization.

1140341131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 144, while the sum is 19.

The square root of 1140341131 is about 33768.9373685344. The cubic root of 1140341131 is about 1044.7481153860.

Adding to 1140341131 its reverse (1311430411), we get a palindrome (2451771542).

The spelling of 1140341131 in words is "one billion, one hundred forty million, three hundred forty-one thousand, one hundred thirty-one".