Base | Representation |
---|---|
bin | 110101000110011110… |
… | …1100111111000010011 |
3 | 101220100020022012112012 |
4 | 1222030331213320103 |
5 | 3332020213122232 |
6 | 124215254453135 |
7 | 11144604655646 |
oct | 1521475477023 |
9 | 356306265465 |
10 | 114034114067 |
11 | 443a8314785 |
12 | 1a1259641ab |
13 | a9a4204053 |
14 | 573ac97a5d |
15 | 2e7635a9b2 |
hex | 1a8cf67e13 |
114034114067 has 2 divisors, whose sum is σ = 114034114068. Its totient is φ = 114034114066.
The previous prime is 114034114049. The next prime is 114034114111. The reversal of 114034114067 is 760411430411.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-114034114067 is a prime.
It is not a weakly prime, because it can be changed into another prime (114034114027) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57017057033 + 57017057034.
It is an arithmetic number, because the mean of its divisors is an integer number (57017057034).
Almost surely, 2114034114067 is an apocalyptic number.
114034114067 is a deficient number, since it is larger than the sum of its proper divisors (1).
114034114067 is an equidigital number, since it uses as much as digits as its factorization.
114034114067 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 8064, while the sum is 32.
Adding to 114034114067 its reverse (760411430411), we get a palindrome (874445544478).
The spelling of 114034114067 in words is "one hundred fourteen billion, thirty-four million, one hundred fourteen thousand, sixty-seven".
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